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Mystery Column | |
| Physics, speakers, and amps can you guess the subject of this article? | ||
| by Richard Clark | ||
| If you have ever visited the CAR SOUND & Performance 12-Volt Forums, you already know that it is a constant source of ideas, questions, and debates. I cannot underestimate the value it can be in the never-ending search for more knowledge about the many facets of our complex, constantly changing industry. As a technical director for CAR SOUND & Performance and AUTOMEDIA magazines, I find it to be an excellent way to keep a finger on the pulse of what the industry cares about both from a technical and business standpoint.
In the last several weeks I have been asked numerous questions about a subject that we have a particular interest in at our A2000 Test Lab. This subject relates to factors that influence the ultimate quality of our systems and, in particular, the workings of speakers and amplifiers. Yet with all its importance, I have found through questioning installers and competitors on the Web that this subject is little understood. So I figure it is a good time for a combination of a physics lesson with a little electrical theory thrown in for good measure. And The Subject Is??? Imagine that we have a large heavy object that we need to move. It is sitting on the floor and is too heavy to lift. The only way we can move it is by exerting a force against it. Lets say that to move the object we have to exert a force of 100 pounds. As we push against this object it resists our efforts to move due to the friction of sliding across the floor. But, as long as we push hard enough, we can overcome the friction of sliding and the object will move. Now, if we want to figure how much work we have done, we can calculate how much weight we have moved over a given distance in a certain amount of time, and that will tell us how much work we have done. As long as we continue to push the object and it resists our pushing, we are doing work. As soon as we stop exerting force on the object it will sit at rest wherever we leave it. The reason we have to do work is because the object is sliding on the floor and the friction caused by the sliding creates unwanted heat. Suppose we create another situation where we also have to exert a similar force against another object. Lets say that this object is a large spring that requires the same 100 pounds of force to compress. From the standpoint of the person doing the pushing, as long as we are pushing against the spring, we probably feel as though we are doing the same amount of work as moving the previous object. The only difference is that now the same force is exerted, but there is no heat generated by friction of an object sliding on the floor. In the case of the spring, the force we apply is stored in the spring, and as soon as we stop pushing on the spring, we become aware of the fact that the spring is now reacting to our pushing by pushing back against us. Unlike the previous object, if we cease to exert force on the spring, it will return to its original position and we have accomplished nothing. Because the stored energy in the spring is returned to its original state, technically speaking, we have done no work. Electrical Analogies In electrical terms we measure work in watts, and to find the amount of work done we simply multiply the voltage by the current and we obtain the amount of wattage. The wattage multiplied by time gives us the total energy. In engineering terms, this is known as real power. As long as we have a resistive load we can multiply volts times amps to get wattage. But just like in the mechanical example where we have resistive and reactive elements (the object on the floor and the spring), we also have resistive and reactive loads in the electrical realm. Reactive loads consist of circuits that contain inductive and capacitive elements. Accurately calculating wattage in such loads is not so easy if AC is flowing. Just like the mechanical spring, if we have a purely reactive load, the energy that is input to the load is returned to the source and no wattage is ever dissipated in the load. We can measure the voltage and current, but we cannot multiply them to get wattage. We now have to apply a term known as Volt-Amperes. Believe it or not, engineers label this measurement imaginary power! Imaginary Power and Real Life The reason this is so prevalent in speakers is because they actually resemble little power generators. The voice coil of the speaker is suspended in a strong magnetic field that is a definition of an electric generator. To see an example of this, take two speakers of similar size and wire them together. Move the cone of one of them back and forth with your hand and watch the other cone move. The movement of the second speaker is a result of the power generated by the first speakers coil! So when an amplifier is driving a reactive speaker as opposed to a resistor, things can be more difficult. The resistor just sits there and turns the electrical power into heat. The speaker, on the other hand, reacts by trying to push current into and pull current out of the output stage of the amp. Since the current is not dissipated as excess heat in the speaker, it sometimes causes additional heating when it is directed back into the amplifier. Resistive and Reactive Ratings We have seen many amps that do a splendid job when driving resistors. But we have seen many of these same amps perform miserably when asked to drive reactive loads. And occasionally there is the super amp that can actually do better when driving a reactive load but these amps amount to less than 1 in 50. So whats our word of advice? If you really want to know how an amp can really drive speakers at high power, read the reports carefully and always check the reactive test, as its the only one that really counts. And if you havent seen the data published here, there might be a good reason to be wary of an amp that looks great driving only light bulbs! |
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